This incredible incident took place in the US state of Virginia, where a dog ran away from home and saved a drowning fawn. The animals then became friends, according to the dog’s owner.
Ralph Dorn’s Goldendoodle dog Harley was not at home that day.
Concerned over the disappearance of a pet, he went searching for him and soon discovered a companion in the nearby lake. To help the young drowning deer, the dog swam to him. It’s unclear how the youngster ended there in the lake. Harley snatched him up and took him to the beach.
The young beast’s physique showed no symptoms of harm, according to Ralph. The man refused to let him go, but a wild animal belongs in the wild. The man observed the dog was acting restlessly again a few days later.
When he opened the door, he heard a deer bleating. When Harley spotted him, he dashed out of the home. The cubs stopped bleating and sniffed each other’s noses while wiggling their tails. Harley peacefully returned to his owner’s house after that.
Dorn published this tale on his Facebook page, and it quickly went viral, with more than 100,000 likes and more than 200 thousand shares.
